Решить 4 химических цепочки.
57,58,60,61

РЕШЕНИЕ

57

C3H7OH + HCl = C3H7Cl + H2O
2C3H7Cl + 2Na = C6H14 + 2NaCl
C6H14 = C6H6 + 4H2
C6H6 + CH3Cl = C6H5CH3 + HCl 
5C6H5CH3 + 6KMnO4 + 9H2SO4 = 5C6H5COOH + 6MnSO4 + 3K2SO4 +14H2O

58

C3H7OH + H2SO4(180) = CH3-CH=CH2 +H2O
CH3-CH=CH2 + HCl = CH3-CH(Cl)=CH3 
CH3-CH(Cl)=CH3 + NaOH(водн = CH3-CH(OH)-CH3 + NaCl
2CH3-CH(OH)-CH3 + H2SO4(140) = CH3-CH(CH3)-O-CH(CH3)-CH3
CH3-CH(CH3)-O-CH(CH3)-CH3 + O2 = CO2 + H2O

60

C3H7OH + H2SO4(180) = CH3-CH=CH2 +H2O
CH3-CH=CH2 + Br2 = CH3-CH(Br)-CH2-Br
CH3-CH(Br)-CH2-Br = CH3-C≡CH + 2HBr
СН3-С≡СН + Н2О =(Н+, Hg[2+])= CH3-C(O)-CH3
2CH3-C(O)-CH3 + H2 = 2CH3-C(OH)-CH3

61

C3H7OH + HBr = C3H7Br + H2O
C3H7Br = C3H6
C3H6 + H2O = C3H7OH
5C3H7OH + 4KMnO4 + 6H2SO4 = 5C2H5COOH + 4MnSO4 + 2K2SO4 + 11H2O 
C2H5COOH =2[H2]= C3H7OH


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